(X^2-3x+1)=(x^2+2x+7)

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Solution for (X^2-3x+1)=(x^2+2x+7) equation: 



(X^2-3X+1)=(X^2+2X+7)

We move all terms to the left:

(X^2-3X+1)-((X^2+2X+7))=0

We get rid of parentheses

X^2-3X-((X^2+2X+7))+1=0



We calculate terms in parentheses: -((X^2+2X+7)), so:

(X^2+2X+7)

We get rid of parentheses

X^2+2X+7

Back to the equation:

-(X^2+2X+7)



We get rid of parentheses

X^2-X^2-3X-2X-7+1=0

We add all the numbers together, and all the variables

-5X-6=0

We move all terms containing X to the left, all other terms to the right

-5X=6

X=6/-5

X=-1+1/5

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